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in Limit, continuity and differentiability by (41.4k points)

From mean value theorem f(b) - f(a) = (b - a) f'(x1); a < x1 < b if f(x) = 1/x, then what is the value of x1?

(A) √(ab)

(B) (a + b)/2

(C) 2ab/(a + b)

(D) (b - a)/(b + a)

1 Answer

+1 vote
by (41.6k points)
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Best answer

Answer is (A) √(ab)

We have

f'(x) = -1/x21

Therefore,

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