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in Trigonometry by (53.3k points)
In a triangle ABC, the vertices A, B, C are at distance of p, q, r from the orthocentre, respectively. Show that aqr + brp + cpq = abc.

1 Answer

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by (53.5k points)
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Best answer

Let H be the orthocentre of triangle ABC Fig. From question, HA = p, HB = q, HC = r

Therefore, 

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