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Prove that |(a,b,c),(a2,b2,c2),(a3,b3,c3)| = abc(a - b)(b - c)(c - a)

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(taking common from a, b, c respectively from, c1,c2,c3)

(taking common (a - b))

from c1, and (b - c) from c2

= (abc)(a - b) (b - c) {(b + c) - (a + b)} 

= abc(a - b) (b - c) (c - a)

= R.H.S.

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