Question

If twice the square of the diameter of a circle is equal to the sum of the squares of the sides of the inscribed triangle ABC, then sin² A + sin²B + sin²C is equal to

(A)  2

(B)  3

(C)  4

(D)  1

Answer 1

Correct option  (A) 2

2(2R)² = a² + b² + c²

Now, use sinA = a/2R