0 votes
in Trigonometry by (53.5k points)

If twice the square of the diameter of a circle is equal to the sum of the squares of the sides of the inscribed triangle ABC, then sin2 A + sin2B + sin2C is equal to

(A)  2

(B)  3

(C)  4

(D)  1

1 Answer

+1 vote
by (53.8k points)
selected by
Best answer

Correct option  (A) 2

2(2R)2 = a2 + b2 + c2

Now, use sinA = a/2R

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.