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If H is orthocentre of triangle PQR then PH + QH + RH is

(A) QR cot P + PR cot Q + PQ cot R 

(B) (PQ + QR + RP) (cot P + cot Q + cot R)

(C)  1/2r(cot P + cot Q + cotR)

(D) None of these

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Correct option  (A) QR cot P + PR cot Q + PQ cot R

PH = 2R′ cos P, QH = 2R′ cos Q, RH = 2R′ cos R (R′: circumradius)

PH + QH + RH = 2R′(cos P + cos Q + cos R) =

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