Question

In a triangle ABC,∠B = π/3 and ∠ π/3. Let D divide BC internally in the ratio 1:3. Then sin∠BAD/sin∠CAD equals

(A)  1/√6

(B)   1/3

(C)  1/√3

(D)   √(2/3)

Answer 1

Correct option  (A)  1/√6

See Fig.

BD : DC = 1 : 3,

To calculate : sin∠BAD/sin∠CAD

Apply sine rule

In ∆ABD,