Dhamaal.app
0 votes
21 views
in Trigonometry by (53.5k points)

In a triangle ABC,∠B = π/3 and ∠ π/3. Let D divide BC internally in the ratio 1:3. Then sin∠BAD/sin∠CAD equals

(A)  1/√6

(B)   1/3

(C)  1/√3

(D)   √(2/3)

1 Answer

+1 vote
by (53.8k points)
selected by
 
Best answer

Correct option  (A)  1/√6

See Fig.

BD : DC = 1 : 3,

To calculate : sin∠BAD/sin∠CAD

Apply sine rule

In ∆ABD,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...