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In a triangle ABC, ∠C = 120°. If h is the harmonic mean of the lengths of the sides BC and CA, then the length of the bisector of ∠BCA is

(A)  h

(B)  h/2

(C)  h/√2

(D)  √3/2 h

1 Answer

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Best answer

Correct option (B)  h/2

Area of  ΔACB = 1/2ab sin 120° = √3/4 ab  ..(1)

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