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Three straight lines are drawn through a point M, lying in the interior of triangle ABC, parallel to its sides. The areas of the resulting three triangles see Fig. are S1, S2 and S3. The area of triangle ABC is

(A)  S1 + S2 + S3

(B)  (√S1 + √S2 + √S3)2

(C)  (S1 + S2 + S3)3/2/(S1 + S2 + S3)

(D) None of these

1 Answer

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Best answer

Correct option (B)  (S1 + S2 + S3)2

See Fig.

S = (√S1 + √S2 + √S3)where S is area of ΔABC

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