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If in a ΔABC, a, b, c are in AP, then it is necessary that 

(A)  2/3<b/c<2

(B)  1/3<b/c<2/3

(C)  2/3<b/a<2

(D)  1/3<b/a<2/3 

1 Answer

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Best answer

Correct option (A), (C)

As a, b, c are in AP we have

a + c = 2b

Now, a + b > c

b + c > a

and a + b > c

⇒3b > 2c

As b + c > a we have

2c > b

Similarly for b/a.

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