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0 votes
3.0k views
in Trigonometry by (53.4k points)

Let ABC be any triangle and P be a point inside it such that ∠PAB = π/18, ∠PBA = π/9, PCA = π/6,∠PAC = 2π/9. Let  ∠PCB = x.

1.  Triangle ABC is an

(A)  equilateral triangle

(B)  isosceles triangle 

(C)  right-angled triangle 

(D)  None of these

3.  Which of the following is true?

(A)  BC > AC

(B)  BC < AB

(C)  AC > AB

(D)  BC = AC 

1 Answer

+1 vote
by (53.3k points)
selected by
 
Best answer

Correct option  (C)(B)(C)

1.  ∠BAC = ∠ACB = 50° 

Therefore, ABC is an isosceles triangle.

2. ∠ABC = 80° 

Therefore, AC is the longest side, AC > AB.

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