Question

A piece of copper having a rectangular cross-section of 15.2 mm x 19.1 mm is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain?

Answer 1

Here A = 15.2 x 19.1 x 10^-6 m²

F = 44,500 N

G = 42 x 10⁹ Nm^-2

Strain = Stress/Shear Modulus of Elasticity

= (F/A)/G = F/AG = 44500/(15.2 x 19.2 x 10^-6) x 42 x 10⁹

= 3.65 x 10^-3