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∫(e^logx + sinx)cosxdx is equal to (A) xsinx + cosx − sin^2x + c

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in Integrals calculus by (41.4k points)

∫(elogx + sinx)cosxdx  is equal to

(A) xsinx + cosx − sin2x + c

(B) xcosx − sin2x + c

(C) xsinx + cosx − (cos2x)/2 + c

(D) x2sinx + cosx − sin3x + c

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1 Answer

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Answer is (C) xsinx + cosx − (cos2x)/2 + c

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