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in Integrals calculus by (41.3k points)

∫sinx(logx)dx is equal to

(A) x/2[sin(lnx) + cos(lnx)] + c

(B) x/2[cos(lnx) - sin(lnx)] + c

(C) x/2[sin(lnx) - cos(lnx)] + c

(D) x[sin(lnx) - cos(lnx)] + c

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Answer is (C) x/2[sin(lnx) - cos(lnx)] + c

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