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Calculate the pH of a buffer solution obtained by mixing 1.5 mole of sodium acetate and 0.09 mole of CH3​​​​​COOH.

{Ka = 1.8 × 10-5 }.

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From Henderson equation of acidic buffer solution we know, 

pH = pKa +log [A-]/[salt]

degree of ionization (∞) = √Kc/C = 3.4e-3

 So,[CH3COO-] = C∞  = 3.4e-3 × 0.09 = 0.306e-3

 So, pH = 4.7 + log [ 0.306e-3]/1.5 = 4.7 + log 0.0204   (log 0.0204  = -1.69)

= 4.7 - 1.69 

= 3.01

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