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in Physics by (24.5k points)

A wire stretches a certain amount under a load. If the load and diameter are both increased to three times, find the stretch caused in the wire.

1 Answer

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by (24.9k points)
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Best answer

Here, Y = (F x l)/(A x Δl)

or, Δl = Fl/AY

⇒ Δl ∝ (F/A)

So, Δl'/Δl = 3F/F x A/9A = 1/3

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