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in Complex number and Quadratic equations by (53.1k points)

If w = α + iβ, where β ≠ 0 and z ≠ 1, satisfies the condition that (w - wz/1 - z) is purely real, then the set of values of z is

(A)  {z : |z| = 1}

(B)  {z :z = (bar)z}

(A)  {z : z ≠ 1}

(A)  {z : |z| = 1, z≠1}

1 Answer

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by (53.3k points)
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Best answer

Correct option (B) {z :z = (bar)z}

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