Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.7k views
in Physics by (24.9k points)

In a test experiment on a model aeroplane in a wind tunnel, the flow speeds on the upper and lower surfaces of the wing are 70 ms-1 and 63 ms-1 respectively. What is the lift on the wing if its area is 2.5 m2. Take the density of air to be 1.3 kg m-3.

1 Answer

+1 vote
by (24.5k points)
selected by
 
Best answer

Here,

v1 = 70 ms-1

v2 = 63ms-1

ρ = 1.3 kg m-3

and A = 2.5 m2

Now, using Bernoulli's theorem (for constant height)

p1 + 1/2 ρv12 = P2 + 1/2 ρv22

⇒ P2 - P1 = 1/2 ρ(v12 = v22)

= 1/2 x 1.3 x |(70)2 - (63)2|

= 605.15 Nm-2

Lift on the wings is,

F = (P2 - P2) x A = 605.15 x 2.5

= 1.51 x 103 N

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...