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0 votes
6.2k views
in Integrals calculus by (41.4k points)

Let f (x) be a continuous function given by f(x) = {(2x, |x| ≤ 1), (x2 + ax + b, |x| > 1)

Find the area of the region in the third quadrant bounded by the curve x = -2y2 and y = f(x) lying on the left of the line 8x + 1 = 0. 

1 Answer

+1 vote
by (41.6k points)
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Best answer

Since f(x) is continuous (Fig.).

 

So, it must be continuous at x = 1, - 1, that is,

Now drawing the given curves.

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