Question

Let g(x) be a function defined on [-1, 1]. If the area of the equilateral triangle with two of its vertices at (0, 0) and [x, g(x)] is √3/4, then the function g (x) is

(A) g(x) = ±√(1 - x²)

(B) g(x) = √(1 - x²)

(C) g(x) = - √(1 - x²)

(D) g(x) = √(1 + x²)

Answer 1

Answer is (A) g(x) = ±√(1 - x²)

Area of equilateral triangle = √3/4

Two vertices are at (0, 0) and [x, g(x)]