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in Integrals calculus by (54.8k points)

Let f: R → R be a continuous and bijective function defined such that f(α) = 0 (α ≠ 0). The area bounded by y = f(x), x = α, x = α - t is equal to the area bounded by y = f(x), x = α , x = α + t ∀ t ∈ R, then

The value of f(2α) is equal to 

(A) f(α

(B) -f(α

(C) f(0) 

(D) -f(0)

1 Answer

+1 vote
by (52.5k points)
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Best answer

Answer is (D) -f(0)

Putting x = a in the given equation, we have

f(0) = - f(2α) ⇒ -f(0) = f(2α)

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