Question

If 1 lies between the roots of the equation ax² + bx - sinθ = 0. a> 0, then a + b is always less than

(A)  − 1

(B) 1

(C) − 3/2

(D) None of these 

Answer 1

Correct option  (B) 1

ax² + bx - sinθ = 0, a > 0

f(1) < 0

⇒ a + b − sin θ < 0

⇒ a + b < sin θ ≤ 1

⇒ a + b < 1