Question

Particular solution of y₁ + 3xy = x which passes through (0, 4) is

(A) 3y = 1 + 11e^{(-3x^2/2)}

(B) y = 1/3 + 11e^{-x^2}

(C) y = 1 + 11/3e^{-x^2}

(D) y = 1/3 + 11e^{3/2x^2}

Answer 1

Answer is (A) 3y = 1 + 11e^{(-3x^2/2)}

Therefore, the solution of given equation is

If the curve passes through (0, 4), then