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+1 vote
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in Physics by (64.7k points)

What is the temperature of the triple-point of water on an absolute scale whose unit interval size is equal to that of the Fahrenheit scale?

1 Answer

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Best answer

The scale and absolute scale are related as:

{TF - 32}/{180} = {TK - 273}/{100}   ...(i)

For another set of temperature, TF and TK,

{TF - 32}/{180} = {TK - 273}/{100}   ...(ii)

Subtracting (i) from (ii), we get

{TF - TF}/{180} = {TK - TK}/{100}

∴ TF - TF = 180/100 (TK - TK)

For TK - TK = 1 K,

TF - TF = 180/100

∴ For a temperature of triple point, i.e., 273.16 K, the temperature on the new scale is

= 273.16 x 180/100

= 191.688

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