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in Permutations and combinations by (46.7k points)
m Men and n women are to be seated in a row, so that no two women sit together. If m > n , then find the number of ways in which they can be seated.

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First arrange m men, in a row in m! ways. Since n < m and no two women can sit together, in any one of the m! arrangement, there are (m + 1) places in which n women can be arranged in  m + 1Pn ways.

Therefore, by the fundamental theorem, the required number of arrangement is

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