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in Complex number and Quadratic equations by (46.7k points)

How many diagonals are there in an n-sided polygon (n > 3)? 

1 Answer

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 The number of lines formed by joining the n vertices of a polygon = Number of selections of 2 points from the given n points

= nC2 = n(n - 1)/2

Out of  nC2 lines, n lines are the sides of the polygon. Hence Number of diagonals = nC2 - n

= n(n - 1)/2 - n = n(n - 3)/2

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