Correct option (A) 450
Let the three-digits of number n = x1,x2,x3.
Since, x1 + x2 + x3 is even, there are following cases:
(a) x1,x2,x3 all are even. So
4. 5. 5 = 100 ways
(b) x1 even and x2 , x3 are odd. So
4. 5. 5 = 100 ways
(c) x1 odd, x2 even, x3 odd. So
5. 5. 5 = 125 ways
(d) x1 odd, x2 odd, x3 even. So
5. 5. 5 = 125 ways
