Here, p = 1 atm = 1 x 1.01 x 105 Pa
V = 25 m3
T = 27°C = 27 + 273 = 300 K
and R = 8.31 J mol-1 K-1
Now pV = uRT
⇒ u = pV/RT = {1.01 x 105 x 25}/{831 x 300} = 1.013 x 103 moles
Now, one mole of a gas contains = 6.023 x 1023 molecules
∴ 1.013 x 103 moles would contain
= 6.023 x 1023 1.013 x 103 = 6.10 x 1026 molecules