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6.3k views
in Permutations and combinations by (52.7k points)

 In a plane, there are 37 straight lines, of which 13 pass through the point A and 11 pass through the point B. Besides, no three lines pass through one point, no line passes through both points A and B, and no two are parallel. Then the number of intersection points the lines have is equal to

(A)  535

(B)  601

(C)  728 

(D)  None of these

1 Answer

+1 vote
by (46.7k points)
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Best answer

Correct option (A) 535 

In the general position, 37 straight lines have 37C2 points of intersection. But 13 straight lines passing through the point A yield one intersection point instead of 13C2 and 11 straight lines passing through the point B yield one intersection point instead of 11C2 .

Therefore, the lines have 37C2 - 13C2 - 1C + 2 points of intersection. This gives

666 – 78 – 55 + 2 = 535

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