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in Differential equations by (54.8k points)

A curve passing through origin is such that slope of tangent at any point is reciprocal of sum of coordinate of point of tangents.

Slope of tangent at ordinate ln 3 is

(A) 1

(B) 1/3

(C) 1/2

(D) - 2

1 Answer

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by (52.5k points)
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Best answer

Answer is (C) 1/2

dy/dx = 1/(x + y)

Let x + y = v. Then

1 + dy/dx = dv/dx

⇒ dv/dx = 1/v + 1 = (1 + v)/v

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