Question

The number of ways in which a necklace can be formed using 6 identical diamonds and 3 identical pearls is

(A)  8!/6!2! x 1/2

(B)  8!/6!2!

(C)  8

(D)  None of these

Answer 1

Correct option (D) None of these

Between 6 identical diamonds we have to place 3 identical pearls which can be grouped as (3, 0), (2, 1) and (1, 1, 1) each having 1, 1 and 1 ways of doing it total ways = 3.