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The number of 4-digit natural numbers in which digit at 1000th places are 1 and exactly one of the digit comes twice are

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The number of 4-digit natural numbers in which digit at 1000th places are 1 and exactly one of the digit comes twice are

(A)  108

(B)  216

(C)  432

(D)  864

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Best answer

3 x 9C2 x 2 = 108 x 2 = 216

3 x 9C2 x 2 = 216

Total number of 4-digit number = 216 + 216 = 432

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