Correct option 1. (A) 2. (B) 3. (B)
1. When 1 all-rounder and 10 players from bowlers and batsman play number of ways = 4C1 ⋅ 14C10
When 1 wicket keeper and 10 players from bowlers and batsman play number of ways = 2C1 ⋅ 14C10
When 1 all-rounder 1 wicket keeper and 9 from batsmen and bowlers play number of ways = 4C1 ⋅ 2C1 ⋅ 14C9
When all 11 players play from bowlers and batsmen then the number of ways = 14C11
Therefore, the total number of selections
= 4C1 ⋅ 14C10 + 2C1 ⋅ 14C10 + 4C1 ⋅ 2C10 ⋅ 14C9 + 14C11
2. If 2 batsmen do not want to play then the rest of 10 players can be selected from 17 other players, number of selection = 17C10.
If the particular bowler does not play then number of selection = 19C11 .
If all the three do not play, number of selection = 17C10 .
Therefore, the total number of selections = 17C10 + 19C11 +
17C11.
3. If the particular batsman is selected then the rest of 10 players can be selected in 18C10 ways.
If particular wicket keeper is selected then rest of 10 players can be selected in 18C10 ways.
If both are not selected the number of ways = 18C11
Therefore the total number of ways = 2⋅ 18C10 + 18C11
= 19C11 + 18C10