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in Permutations and combinations by (52.7k points)

If a cricket team of 11 players is to be selected from 8 batsmen, 6 bowlers, 4 all-rounder and 2 wicket keepers, then

1. The number of selections when at most 1 all-rounder and 1 wicket keeper will play is

(A)  4C114C10 +  2C114C10 +  4C12C1 2C114C9 + 14C11 

(B)  4C115C11 + 15C11 

2. Number of selection when 2 particular batsmen do not want to play when a particular bowler will play is 

(A)  17C10 + 19C11 

(B)  17C10 + 19C11 + 17C11 

(C) 17C10 + 20C11 

(D) 19C10 + 19C11

3.  The number of selections when a particular batsman and a particular wicket keeper do not want to play together is

(A)  2⋅ 18C10

(B)  19C11 + 18C10 

(C)  19C10 + 19C11 

(D)  None of these 

1 Answer

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by (46.7k points)
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Best answer

Correct option 1. (A) 2. (B) 3. (B)

1.  When 1 all-rounder and 10 players from bowlers and batsman play number of ways = 4C114C10 

When 1 wicket keeper and 10 players from bowlers and batsman play number of ways = 2C114C10 

When 1 all-rounder 1 wicket keeper and 9 from batsmen and bowlers play number of ways = 4C12C1 14C9

When all 11 players play from bowlers and batsmen then the number of ways = 14C11 

Therefore, the total number of selections

= 4C114C10 + 2C114C10 + 4C12C1014C9 + 14C11

2. If 2 batsmen do not want to play then the rest of 10 players can be selected from 17 other players, number of selection = 17C10.

If the particular bowler does not play then number of selection = 19C11 .

If all the three do not play, number of selection = 17C10 .

Therefore, the total number of selections = 17C10 + 19C11 +

17C11.

3.  If the particular batsman is selected then the rest of 10 players can be selected in 18C10 ways.

If particular wicket keeper is selected then rest of 10 players can be selected in 18C10 ways. 

If both are not selected the number of ways  = 18C11

Therefore the total number of ways =   2⋅ 18C10 + 18C11

= 19C11 + 18C10

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