Question

The solution of the primitive integral equation (x² + y²)dy = xydx is y = y(x). If y(1) = 1 and y(x₀) = e, then the value of x₀ is 

Answer 1

Answer is (c) √3e

Explanation:

The given differential equation is

(x² + y²)dy = xydx

which is a homogeneous differential equation.

– (x²/2y²) + log |y| = c

When x = 1, y = 1, then c = – 1/2  

Thus, the equation of the curve is