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+1 vote
5.3k views
in Differential equations by (33.1k points)

If y' = y + 1 and y(0) = 1, the values of y(ln2) is ...

1 Answer

+2 votes
by (36.4k points)
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Best answer

Given differential equation is

y' = y + 1

log |y + 1| = x + c

when x = 0, y = 1, then c = log 2

Hence, the equation of the curve is

log |y + 1| = x + log 2

When x = ln 2, then

y + 1 = 4 

y = 3

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