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in Differential equations by (33.1k points)

Let f : [1, ∞) → [2, ∞) be a differentiable function such that f(1) = 2. If 6∫f(t) dt for t ∈ [0,x] = 3xf(x) – x3 – 5 for all x ≥ 1, the value of f(2) is ...

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Given equation is

y/x = x + c

When x = 1, y = 2, then c = 1

Hence, the equation of the curve is

y/x = x + 1 

when x = 2, then y = 6

Thus, the value of f(2) is 6.

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