Question

A cyclist is riding with a speed of 27 km/h. As he approaches a circular turn on the road of radius 80 m, he applies brakes and reduces his speed at the constant rate of 0.50 m/s every second.What is the magnitude and direction of the net acceleration of the cyclist on the circular? 

Answer 1

Let us suppose, the cyclist applies brakes at the point A of the circular turn.Then retardation produced due to brakes (a₁) will act opposite to the velocity (v) Thus,

a_T = -0.5 ms^-2

Total acceleration is given by

If θ be the angle between the total acceleration and the velocity of the cyclist, then