Thre vectors v1, v2, v3 involve 9 unknown quantities. Since, we are given six equations involving 9 unknown quantities, it is not possible to have uniquely 3 vectors-satisfying these conditions.
As v1.v2 = 4, let us consider v1 = 2k.
Thus, one possible set of vectors is
v1 = 2k, v2 = i + 2k, v3 = – 2i + 4j + 3k.
