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in Vector algebra by (36.3k points)

Let P, Q, R, S be the points on the plane with position vectors –2i – j, 4i, 3i + 3j and –3i + 2j respectively. The quadrilateral PQRS must be a 

(a) parallelogram, which is neither a rhombus nor a rectangle 

(b) square 

(c) rectangle but not a square 

(d) rhombus but not a square.

1 Answer

+1 vote
by (33.0k points)
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Best answer

Answer is (a) parallelogram, which is neither a rhombus nor a rectangle

Explanation:

Let M be the mid-point of PR. Then the position vector of M is

So, PQRS is not a rectangle.

Therefore, PQRS is a parallelogram, which is neither a rhombus nor a rectangle.

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