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+1 vote
4.8k views
in Chemistry by (50.2k points)

3 gram of acetic acid is mixed in 250 mL of 0.1 M HCl. This mixture is now diluted to 500 mL. 20 mL of this solution is now taken is another container 1/2 mL of 5M NaOH is added to this. Find the pH of this solution. Find the pH of this solution. (log 3 = 0.4771, pKa = 4.74)

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1 Answer

+1 vote
by (48.6k points)

The answer is (5.22)

m mole of acidic acid in 20 mL = 2 

m mole of HCl in 20 mL = 1

m mole of NaOH = 2.5 

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