Correct Answer is: (4) 39
Equiv. of HCl taken = 60 × 2 × 10–3
Equiv. of HCl present after the reaction = 20 × 1 × 10–3
∴ Equiv. of HCl utilized = 100 × 10–3
∴ 100 × 10–3 equiv. of metal carbonate = 6.90 gm
∴ 1 equiv. of metal carbonate
= 6.69/10-1 = 69 gm
∴ equiv. wt. of metal = 69 – 30 = 39
[becuase equiv. wt. of carbonate = 30]