Question

A plane passes through (1, 2, 3) and is perpendicular to two planes x = 0 and y = 0. The distance of the plane from the point (0, –1, 0) equals ..........

Answer 1

The equation of any plane passing through (1, 2, 3) is

a(x – 1) + b(y – 2) + c(z – 3) = 0

which is perpendicular to x = 0 and y = 0

So, a = 0, b = 0.

Thus, the equation of the plane is

c(z – 3) = 0 

(z – 3) = 0 

Thus, the required distance from (0, –1, 0) to the plane (z – 3) = 0 is