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+1 vote
3.8k views
in Chemistry by (56.8k points)

The bond dissociation energy of gaseous H2, Cl2 and HCl are 104, 58 and 103 kcal mol–1 respectively. The enthalpy of formation for HCl gas will be

(1) – 44.0 kcal 

(2) – 22.0 kcal

(3) 22.0 kcal 

(4) 44.0 kcal

1 Answer

+2 votes
by (50.2k points)
selected by
 
Best answer

Correct Answer is: (2) – 22.0 kcal

Divide equation (1) and (2) by 2, and then add

Subtracting equation (3) from equation (4)

∴ Enthalpy of formation of HCl gas = – 22.0 kcal

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