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+1 vote
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in Three-dimensional geometry by (36.4k points)
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A line L passing through the origin is perpendicular to the lines L1 :(3 + t)i + (–1 + 2t)j + (4 + 2t)k and L2 :(3 + 2s)i + (3 + 2s)j + (2 + s)k, where –∞< t, s < ∞

Then, the coordinate(s) of the point(s) on L2 at a distance of √17 from the point of intersection of L and L1 is

1 Answer

+2 votes
by (33.1k points)
selected by
 
Best answer

Answer is 

The common perpendicular is along

Since, point P is arbitrary point on line L2

Therefore, P = (3 + 2s, 3 + 2s, 2 + s).

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