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How how much bacl2 would be needed to make 250 ml of solution having same concentration of a chlorine negative as the one containing 3.78 gram of NaCl per 100ml ?

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Best answer

Two solution of same concentration would mean that the molarity of both the solutions is equal. Therefore, first we need to calculate the molarity of NaCl solution.

Mass of NaCl = 3.78 g

Molar Mass of NaCl = 58.5 g/mol

Volume of NaCl Solution = 100 mL = (100 / 1000) L

(Molarity)NaCl = Mass of NaCl in grams / (Molar Mass of NaClxVolume of solution in L)

(Molarity)NaCl = (3.78 x 1000) / (58.5 x 100)

(Molarity)NaCl = 0.65 mol/L

Now, (Molarity)NaCl = (Molarity)BaCl2 

Mass of BaCl2 = m g

Molar Mass of BaCl2 = 208.33 g/mol

Volume of BaCl2 solution = 250 mL = (250 / 1000) L

(Molarity)BaCl2 = Mass of BaCl2 in grams/(Molar Mass of BaCl2xVolume of solution in L)

0.65 = (m x 1000) / ( 208.33 x 250) g

m = (0.65 x 208.33) / 4 g

m= 33.8 g

Hence, 33.8 g of BaCl2 is required to make 250 ml of solution having same concentration of chloride as one containing 3.78g NaCl per 100ml. 

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