Question

The velocity of a particle 6 ms^-1 eastwards changes to 8 ms^-1 northwards in 10s. What is the magnitude of the average acceleration during this interval of time?

(a) 1.4 ms^-2.

(b) 1 ms^-2.

(c) 0.2 ms^-2.

(d) none of the above

Answer 1

Answer is (b) 1 ms^-2.

∆ν = (j8 – I6) ms^-1. here ∆ν = 10 ms^-1 and ∆t = 10s.

Therefore a = ∆ν/∆t = 1 ms^-2.