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0 votes
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in Physics by (50.2k points)

5 g of ice at 0°C is dropped in a beaker containing 20 g of water at 40°C. What will be the final temperature?

(1) 16 

(2) 17 

(3) 19 

(4) 20

1 Answer

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Best answer

Correct Answer is: (1) 16 

Let final temperature be = θ

Heat taken by ice = m1L + m1c1 Δ θ1

= 5 × 80 + 5 × 1 ( θ – 0)

= 400 + 5θ

Heat given by water at 40°C

= m2c2 Δ θ2 = 20 × 1 × (40 – θ )

= 800 – 20θ

As Heat given = Heat taken

800 – 20θ =400 + 5θ

20θ = 400

θ = 400/25 = 16° C

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