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in Binomial theorem by (52.7k points)

If A1,A are the two AMs between two numbers a and b and G1, Gare two GMs between same two numbers, then A1 + A2/G1.G2 = 

(a)  a +b/ab

(b)  a + b/2ab

(c)  2ab/a + b

(d)   ab/a + b

1 Answer

+1 vote
by (46.7k points)
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Best answer

Correct option  (a)  a + b/ab

Given that a, A1, A2,b are in AP. Therefore

a,G1,G2,b are in GP. Therefore

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