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+1 vote
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in Physics by (33.0k points)

The range of projectile when fired at 75° with the horizontal is 0.5 km. What will be its range when fired at 45°. 

(a) 0.5 km. 

(b) 1.0 km 

(c) 1.5 km 

(d) 2.0 km.

1 Answer

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by (36.3k points)
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Best answer

Answer is (b) 1.0 km

R1 = u2 sin2θ/g = u2 sin150°/g = u2 sin30°/g = u2/2g

= u2 sin90°/g = u2/g.

therefore R2 = 2R1

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