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If |x|<1, then the coefficient of x^5 in the expansion of (1 - x)loge (1 - x) is

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in Binomial theorem by (52.7k points)

If |x|<1, then the coefficient of x5 in the expansion of (1 - x)loge (1 - x) is

(A)  1/2 

(B)  1/4 

(C)  1/20 

(D)  1/10 

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1 Answer

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Correct option  (C)  1/20

(1 - x)loge(1 - x)

Hence, coefficient of x5 = 1/4 - 1/5 = 1/20

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